Recent content by bob dobilina

Thanks rude man, I should be able to figure it out from here...

Hi haruspex. Second part of the question here. Would appreciate any advice on this one. The only thing I can come up with is reversing the current of solenoid, but not sure how to prove this with the formulas.

Ok, thank you.

The magnetic field is acting in a clockwise direction, which is why it pushes the electron the right side of the screen. Hmmm, I know that E=Vq, therefore Vq=(1/2)mv2 so i need to find v. Since the problem tells me the acceleration in the magnetic field, would I be able to use...

For d I am using the distance of the screen from the CRT, which is 1 meter. For a, I am using the acceleration of the electrons in the magnetic field, which is 9.08 x 1014 m/s^2

a and d are given to us in the question. This formula is one of the kinematics formula provided to me. V final 2 = Velocity initial 2 + 2ad

v(final)2=v(initial)2 + 2ad Initial velocity is 0 because it is at rest, so final velocity will be equal to whatever "2ad" turns out to be. So E will look something like this E = (1/2)m(2ad)2 Therefore, potential difference should be V=E/q V=((1/2)m(2ad)2)/q I am unsure if it is okay if I use...

Homework Statement A solenoid is placed beneath a CRT that produces a magnetic field of 1.10 x -2. The CRT is 1 meter away from a screen. The electrons that make up the beam were accelerated from rest through a potential difference(V) at the beginning of the CRT. Acceleration of the electrons...

Sorry I should have included the units in my ratio. Awesome. Thank you for the help.

Alright. I figure the charge to mass ratio should be: Fm=Fc qvB = (mv2)/r (q/m)=v/(Br) When i crunch the numbers I get an answer of 1.7647 x 10 11 Same as an electron..what do you think of this?

Would i be able to manipulate Fm=Fc to find q (the charge). qvB=mv2/r q=(mv)/(rB) ?

Homework Statement A Phosphorous 34 decays and emits a particle. A JJ Thomson experiment is done to find out the charge to mass ratio of this particle. The particle moves undeflected through mutually perpendicular magnetic and electric fields of 2.00 x 10-3 T and 1.08 x 104 N/C, respectively...

Could I use the total kinetic energy to find the mass defect by manipulating e=mc2? If so, once I find the mass defect, can I add that mass to the mass of He4 and the neutron to get the mass of He5?

KE of He5 would be 0 since the problems states it at rest before the reaction. KE of He4 is given to us. KE of Neutron could be found using KE=mv2/2. The mass is given to us in the question, and we already found velocity. Ok, so what do i do when I found the KE? Am i going to be using E=mc2?

Would total KE after fission be equal to KE of He4 plus the KE of the neutron? To find the KE of the neutron would I be able to just use mv2/2? Since I already found the velocity of the neutron in the previous question?