Recent content by Bob4321
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Angular Momentum of a Uniform Rod
For my problem the (1-cos45) is .48- Bob4321
- Post #6
- Forum: Introductory Physics Homework Help
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Angular Momentum of a Uniform Rod
Ok I have figured out that the .2 is from 1-cos but I still keep getting the wrong answer! Could you solve it so I can see what you did?- Bob4321
- Post #5
- Forum: Introductory Physics Homework Help
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Angular Momentum of a Uniform Rod
Solution Attempt: Ok so for A: ω1=((1/3)(2.8)(1.52))/ ((1/3)(2.8)(1.52))+m(1.12)√3(9.81m/s2)/1.5= (4.429kg/s)/(2.1kg)+1.21m ½(4.429kg/s)2/(2.1kg)+1.21m I don't know what to do now. Where did they get the .2 from in their example?- Bob4321
- Post #3
- Forum: Introductory Physics Homework Help
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Angular Momentum of a Uniform Rod
<< Mentors have notified the OP to show their Attempt at a Solution >>[/color] 1. Homework Statement A uniform rod of length L1 = 1.5 m and mass M = 2.8 kg is supported by a hinge at one end and is free to rotate in the vertical plane. The rod is released from rest in the position shown. A...- Bob4321
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- Angular Angular momentum Momentum Rod Uniform
- Replies: 6
- Forum: Introductory Physics Homework Help