Recent content by Bobbert

Thanks. The logic / ideas make sense but I am having trouble getting your formula. Could you show an extra step or two?

So, I know what happens with the first two cases, but what if the dielectrics are on a diagonal?

Thanks I am going to assume here g = 9.81 not -9.81 or else the inside of the root could fail.

Can you show all your work on how you got t, because I keep getting a negative in front. also fixed my final t line.

Ok so I did: dy=v1yt+1/2ayt2 -1.1=v1yt-4.905t2 9.81 for g here. 4.905t2-v1yt-1.1 t=-v1y+/-(((-v1y)2-4(4.905)(-1.1))^.5)/2(4.905) t=-vsinθ+(((-vsinθ)2+21528)^.5)/9.81 (has to be positive or time will be negative) then from before: 1/2mv2=1/2kx2 v=((kx2)/m)^1/2 but I only want the x speed...

Sorry about the t. if s0 stands for displacement (it should be -1.1 then?), then I set s = 0 and do the quadratic? EDIT: Also why is yours +1/2at^2 where as mine and cyosis is -1/2at^2 ?

I am looking for horizontal range. My equation sheet has the formula dy=v2t-1/2at2 what does y0/s0 stand for?

Yes it is an experiment I am doing at home and I am not too worried about resistance. Ok, I am going to assume it is v2=v1+at because I need time, and I don't have distance. t=v1sinθ/a because v2 is 0 halfway up so t=2(vsinθ/a) still am not accounting for the 1.1m off the ground (not sure how...

Homework Statement So I made a spring launcher that will fire marbles. I need to derive a general formula for finding range for any given angle and x value.Homework Equations 1) v22=v12+2ad 2) Ek=Es 3) 1/2mv2=1/2kx2 4) d=v*t This projectile was shot from 1.1m off of the ground. The Attempt at...

wow, it is way to late. How did I mess that up.

Homework Statement Find the max height of a projectile fired at an angle of 30 degrees if it's inital speed is 0.714m/s. (this is a lab so I have other data that might be needed) Homework Equations V22=V12+2ad The Attempt at a Solution V22=V12+2ad 0=(0.714sin30o)2+2(-9.81)(d) d=19.62-0.127449...

Amazing link man! Thank you.

thanks guys.

Ahh shucks.

Is there an online source where I can view it?