What Went Wrong? Calculating the Max Height of a Projectile at a 30 Degree Angle

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Homework Help Overview

The discussion revolves around calculating the maximum height of a projectile launched at a 30-degree angle with an initial speed of 0.714 m/s. Participants are examining the application of kinematic equations in this context.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are analyzing the use of the kinematic equation V² = V₁² + 2ad to find the maximum height. There is a focus on the practicality of the calculated height and questioning the validity of the mathematical approach used.

Discussion Status

The discussion is ongoing, with participants questioning the calculations and the assumptions made regarding the projectile's motion. Some have suggested that the math may not yield a practical result, indicating a need for further exploration of the problem.

Contextual Notes

There is mention of additional data that may be relevant to the problem, but it is not provided in the current posts. Participants are also reflecting on potential mistakes made in their calculations.

Bobbert
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Homework Statement


Find the max height of a projectile fired at an angle of 30 degrees if it's inital speed is 0.714m/s.
(this is a lab so I have other data that might be needed)

Homework Equations


V22=V12+2ad

The Attempt at a Solution


V22=V12+2ad
0=(0.714sin30o)2+2(-9.81)(d)
d=19.62-0.127449
d=19.49m

Now this answer is not practical at all. There is no way my projectile went that high. Maybe a couple meters, but not 19.5m. Where did I go wrong?
 
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Bobbert said:
3. The Attempt at a Solution
V22=V12+2ad
0=(0.714sin30o)2+2(-9.81)(d)
d=19.62-0.127449

d=19.49m

Now this answer is not practical at all...

Maybe it's your math that isn't practical?

Shouldn't you get a result that is a small number divided by a big number?
 
If v2=0

then 0=V12-2(9.81)d

d=\frac{V_1^2}{2(9.81)}
 
wow, it is way to late. How did I mess that up.
 

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