# Recent content by Brendy

1. ### Estimating complex integral

Homework Statement I need to establish the estimate and inequality |\int_{C} e^{iz^{2}}dz| \leq\frac{\pi(1-e^{-R^{2}}}{4R} < \frac {\pi}{4R} where C={z(t)=Re^{it},t\in[0,\fraq{\pi}{4}] Homework Equations The Attempt at a Solution I thought perhaps I could use the ML equality but...
2. ### Complex analysis problem

Ah, thanks guys. I confused myself with the exponential for a bit.
3. ### Complex analysis problem

Just thought a bit more on that solution... Isn't it undefined everywhere since e2in\pi=1 and therefore the denominator is 0?
4. ### Complex analysis problem

That's exactly what he did. It's a nice way to eliminate that annoying exponent that I didn't think of until I saw him do it. The next part is just rearranging what he had to get it in the form z= It isn't an easy subject. Unfortunately, the prerequisite subject for complex analysis at my uni...
5. ### Complex analysis problem

Thanks, jackmell. I didn't think of doing that. Once I did, the rest of the problem proved to be simple.
6. ### Complex analysis problem

It would, wouldn't it! That equation should have an =0 at the end. My apologies.
7. ### Complex analysis problem

Alright, I've got (r23ei\theta-ei\pi)23-r23e23i\theta I don't recall any way to combine the two exponents. Expanding those brackets are going to be a mess, I think, and probably unnecessary since I'm not trying to find the solutions exactly.
8. ### Complex analysis problem

Homework Statement Consider the equation (z-1)^23 = z^23 Show that all solutions lie on the line Re(z)=1/2 How many solutions are there Homework Equations The Attempt at a Solution Really have no idea. I figured polar form might be helpful somehow so I converted it and got...
9. ### Sodium emission spectrum

Oh, you mean light emitting diodes? I can't speak for OP but in my lab we had curtains that closed off each bench from the rest of the lab so there was very little light other than that from the sodium lamp. There may have been a little red light on the power switch on the power supply but...
10. ### Sodium emission spectrum

I'm not sure I know what a red led indictor lamp is...
11. ### Sodium emission spectrum

I think I'm doing the same experiment as OP and the lab manual states that the sodium D-line is the yellow line which is actually a doublet. I'm not sure what the red line is either as it was too faint to get an accurate measurement. As for Vanadium 50's hint, it seems that he's implying that...
12. ### Fixed point iteration to find the roots of 0=x-tan(x)

After rewriting it so that x_new... line is now x_new= atan (pi + x_old) it converged within 6 iterations. So is that just a fluke then? It is giving me the correct number to find the roots though. I don't follow post #51 at all I'm sorry.
13. ### Fixed point iteration to find the roots of 0=x-tan(x)

I didn't write the code. I modified an existing program that was solving x_n+1 = e^-x_n Which solution are you referring to? Even changing the initial guess to something further away from the root such as 0.5 sees it converging within 6 iterations.
14. ### Fixed point iteration to find the roots of 0=x-tan(x)

Thanks alot, you've been a massive help. One last thing, what are f_old and f_new doing in my code? After I edit the line x_new.... to the expression for theta, it will converge on a root but I'm not sure what those two lines after that mean. Are they needed? Also, is it supposed to converge so...
15. ### Fixed point iteration to find the roots of 0=x-tan(x)

Do you mean at the end of running the algorithm? Also, when I solve for x, the x represents the roots, right? Not just another initial guess? Or do I use what I find x to be as the next initial guess?