Recent content by Bucs44

What needs to be parsed? AB on the left and CD on the right?

Homework Statement I am having a hard time figuring out this postfix expression and turning it into a binary tree: ABCD+*/E- The Attempt at a Solution what's confusing me is the left side of the tree - the ABCD - I know the right side of the tree would look like this: - is the root...

The order is just the number of "previous" terms, in which case the order is 2

=2(2An-1 + 1) + 1 =2^2An-1 + 2 + 1 Is this right?

Homework Statement Here's my problem - Give the order of linear homogeneous recurrence relations with constant coefficients for: An = 2na(n-1) The Attempt at a Solution I have no idea on how to start this problem - Any help would be greatly appreciated.

So P(2) + P(4) + P(6) = 1/8 + 1/8 + 1/8?

Geez - thanks for the great input there! Some of us aren't math wizz's.

That's just it - I don't understand this. I guess I see where P(2)*P(3) = P(6) but where I get lost is P(1)=3P(2), and P(1)+P(2)+..P(6)=1.

Homework Statement A die is loaded so that the numbers 2 through 6 are equally likely to appear but that 1 is 3 times as likely as any other number to appear. What is the probability of getting an even number?Homework Equations This is where I become lost - I'm not sure how to get the...

Dontdisturbmycircles, I can't thank you enough for your help - It makes sense now! Here's the final answer: 32x^5 - 240x^4d + 720x^3d^2 - 1080x^2d^3 + 810xd^4 - 243d^5

Ok - Here's where I am at this point: 5!/5!0! (32X^5) + 5!/4!1! (16x^4)(-3d) + 5!/3!2! (8x^3)(9d^2) + 5!/2!3! (4x^2)(-27d^3) + 5!/1!4! (2x)(81d^4) + 5!/0!5! (-243d^5) Here is where I'm stuck - I have 32^5 + 5*4*3*2/4!1! ?? Is this right?

I'm still confused on that. Breaking down the possibilities is where I get confused: (a + b)^5 = aaaaa + aaaab + aaabb + aabbb + abbbb + bbbbb I'm lost!

I'm really confused when it comes to this stuff. I'm stuck on this problem: (2c - 3d)^5 I have no idea where to begin. Please help!

Is this right?

Right - Because there are 18 Vesuvians and Jovians, the Martians can either fit in the front of the line, middle or end of the line. In which case there would be 19 spots where they could fit in line. P(19,5) = 1,395,360