Recent content by BuhRock

So when is asks if there is evidence that acceleration is constant, how do I need to prove that?

1. A car rolls down such an incline from rest, starting at different positions on the incline. If the car coasts distances of .7430036cm, .9169641cm, 2.025999cm, and 1.61088cm, starting from rest each time and requires respective times of 3.5 sec, 7 sec, 7.25 sec, and 7.75 sec, is there...

1. s = v0t + .5at^2 , solve for a 2. I don't know any 3. I don't know where to begin. I was thinking that you divide .5 from a to make it s/.5 = v0(t) + at^2.

Oh I see, so what if it asks for this? How fast is it then going when it hits the ground, and how long after the initial toss does it first strike the ground?* I still never got an answer if when it says downward uniform acceleration of 10m/s^2 means that for every second, the avg...

I understood everything up until you say set velocity equal to 0 and solve for t. If t = v/a Then how can you do 0/a? It will always be 0?

Ok, so I got that. It takes 1.5 seconds to reach it's maximum height of 23.25 meters.

Oh, I had 10, instead of -10. That's because it's a downward acceleration?

So that would be adding 12 to 21.5, which is 33.5m. So this is the highest point the ball reaches?

How can I use those if I don't have time? I also found this equation: s = sqrt(2(a)(12)+(15)^2) which gives me 21.5 meters. What is the 21.5 meters? Is that the highest point in the air?

1. A ball is tossed upward at 15 meters / second from a height of 12 meters above the ground.* Assume a uniform downward acceleration of 10 m/s^2 (an approximation within 2% of the 9.8 m/s^2 acceleration of gravity).* How high does it rise and how long does it take to get to its highest...

I tried taking the equation s = .5(vo+vf)t and rearranging it to get vf, which got me 10.7 which can't be right. What is the delta x in those equations? I have initial velocity, which is 24 m/s. I have average velocity which is 17.36(Displacement / time). So, from here. What do I use?

With uniform acceleration, can you say that average velocity * 2 = vf? Well I don't have acceleration. I was thinking I would use the second one, but I don't have vf. What is delta x?

I was saying that the vf being 477.6 doesn't make sense. Also, how can I find a with just t.

1. Determine the acceleration of an object whose velocity is initially 24 cm/s and which accelerates uniformly through a distance of 66 cm in 3.8 seconds. 2. s = (vf + v0) / 2 * t, 3. I tried rearranging that formula but I got vf= 477.6. This just doesn't make any sense

I sent you a message about this.