How Do You Calculate Final Velocity with Uniform Acceleration?

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Homework Help Overview

The discussion revolves around calculating the final velocity of an object under uniform acceleration, given its initial velocity, distance traveled, and time. Participants are exploring the application of kinematic equations to derive the necessary values.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants attempt to rearrange kinematic equations to solve for final velocity and acceleration. Questions arise regarding the interpretation of formulas and the relationship between average velocity and final velocity.

Discussion Status

Some participants express confusion over the calculated final velocity, questioning its validity. Others suggest using different kinematic equations to clarify the relationships between the variables involved. There is an ongoing exploration of how to derive acceleration from the given information.

Contextual Notes

Participants note the challenge of determining acceleration without having all necessary values, such as final velocity. There is also mention of potential misinterpretation of the equations being used.

BuhRock
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1. Determine the acceleration of an object whose velocity is initially 24 cm/s and which accelerates uniformly through a distance of 66 cm in 3.8 seconds.




2. s = (vf + v0) / 2 * t,



3. I tried rearranging that formula but I got vf= 477.6. This just doesn't make any sense
 
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BuhRock said:
1. Determine the acceleration of an object whose velocity is initially 24 cm/s and which accelerates uniformly through a distance of 66 cm in 3.8 seconds.




2. s = (vf + v0) / 2 * t,



3. I tried rearranging that formula but I got vf= 477.6. This just doesn't make any sense

Didnt you just find the final velocity? they asked for acceleration, so you should be solving for that since you have the time. you can find out the acceleration
 
I was saying that the vf being 477.6 doesn't make sense. Also, how can I find a with just t.
 
BuhRock said:
I was saying that the vf being 477.6 doesn't make sense. Also, how can I find a with just t.
Determine the kinematic equation that you would have to use...

Vf = Vi + at
Delta x = .5(vf+vi)t
Delta x = Vi(t)+.5a(t^2)
Vf^2 = Vi^2 + 2a(delta x)

Choose which one you would use, and solve for Vf.
 
BuhRock said:
2. s = (vf + v0) / 2 * t,



3. I tried rearranging that formula but I got vf= 477.6. This just doesn't make any sense
You apparently interpreted the equation as being s = (vf + v0) / (2 * t)

However the equation is equivalent to s = ((vf + v0) / 2) * t
 
With uniform acceleration, can you say that average velocity * 2 = vf?

Aggression200 said:
Determine the kinematic equation that you would have to use...

Vf = Vi + at
Delta x = .5(vf+vi)t
Delta x = Vi(t)+.5a(t^2)
Vf^2 = Vi^2 + 2a(delta x)

Choose which one you would use, and solve for Vf.

Well I don't have acceleration. I was thinking I would use the second one, but I don't have vf. What is delta x?
 
Last edited:
You can find average velocity. From that and the initial velocity you can find final velocity. Then acceleration.
 
I tried taking the equation s = .5(vo+vf)t and rearranging it to get vf, which got me 10.7 which can't be right. What is the delta x in those equations?

I have initial velocity, which is 24 m/s. I have average velocity which is 17.36(Displacement / time). So, from here. What do I use?
 
vf = 10.737 m/s is about right.

The initial velocity is greater than the average velocity, so the object is slowing down.

Now find the acceleration.
 

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