Recent content by c7ng23

I think maybe you cannot use it because energy is lost (i.e we are not counting heat). Is this correct?

Why don't you get the right answer if you only use conservation of energy-> initial KE = final KE + final U \frac{1}{2} mv^2 = 2LMG + \frac{1}{2} m(v/2)^2

Can you show what equations you used? Kinetic friction should be used for surfaces moving relative to each other.

A diopter is 1/f measured in meters. So 16 diopters would be 1/16 meters.

If you remember that isobaric means the pressure remains constant you can find the temperature during the expansion. Then during the compression, the problem says the temperature does not change because it is an isothermic compression. Find the temperature from the ideal gas equation: \ PV=nRT...

I wanted to update- I found the area under the curve by integrating and it matched the answer as if we considered the energy stored in the compression of the springs separately: \int ^{d1}_{0}k_{1}x +\int ^{d2}_{d1} (k_{1}+k_{2})x +k_{1}d_1 \ \frac{1}{2} k_{1}d_{1}^2 +...

Homework Statement There are two springs, one long spring of constant k1 and it is inside a smaller spring of constant k2. Both springs follow Hooke's Law. A box of mass M moves without friction and compresses spring 1 a distance d1 where it hits spring 2. Spring 1 and 2 then compress further...