How do I convert gph to psi?....
Here is the deal, we are testing a 24" pipe for leaks doing a pressure test. the pressure at the pipe in question is 185 psi, and it lost 4 psi. I have a chart showing the allowable loss in GPH, but I dont know how to convert to PSI. Since this was a test...
1.I am given a zenith angle of 73 (degrees) 17'30"
2. How do I compute (2360/5280)times cos(73 degrees, 17'30") with a ti 89 and a regular scientific calculator?
3. The solution is .446 degrees
Thank you sooo very much.
http://wps.prenhall.com/wps/media/objects/3076/3149958/studypak/questions/html/Ch16/9e_16_43.html
That is the image of the problem, which includes a solution. PROBLEM- Besides being really confused on their work, the solution they give and the solution in the back of my book are both...
http://wps.prenhall.com/wps/media/objects/3076/3149958/studypak/questions/html/Ch16/9e_16_43.html
That is the image of the problem, which includes a solution. PROBLEM- Besides being really confused on their work, the solution they give and the solution in the back of my book are both...
thank you both very much.
Mindscrape: The difference is that the ball has tangental and normal acceleration components, however using energy they should both come out to be the same speed, because neither of them ever stops. but because their acceleration and velocity vectors are so...
Learning physics: The velocity is the same at impact because the vx component does not change, but what of the Vy component? It makes sense that it doesnt actually increase more than its given velocity.. but not sure why its the EXACT same.
So heres my plan- Ill set up the energy equation...
The ball is fired with an intial velocity of 10 m/s up a smooth inclined plane. The planes dimensions are 1.5 m high and 2 m long on the bottom so the hypotenuse of the plane is sqrt (1.5^2+2^2). It has enough velocity to make a parabolic shape as it is coming off the plane. .. Confusing I know.
Homework Statement
the 2 kg ball is fired from point a with an Vo of 10 m/s up the smooth inclined plane. The angle is 37 degrees, it gives me the planes dimentions the ball rolls on, it is 1.5 m high and 2 m wide. It asks the distance in the x it lands. Also the velocity with which it...
yes, i redid everything as maximum speed and got 118.8.
i found the power dissapated= 325*30m/s divded by 550 to convert and got 17.7 HP. Then I found the max energy using the max velocity as 1/2mv^2, converted it to power- 101.6 HP, added both since the power dissipated will need to be...
me too. Im wondering if the Pmax eq is different, I remember from physics it being slightly different but I cant find a difference.. I have the answer already, it should be 119 HP.
thanks for the reply. But your going to have to spell it out for me as I have tried everything known to man.
what does the total energy have to do with it?
I know the mass, times the acceleration found through kinematics, and the fictional force is 375, add it all together to get the total...