Thanks for the reply. Am I getting warmer here:
By using the value for B = μ0 (i) / 2 π r = 4πx10-7 (i) / 2 π r
we now have current, i, in the eqn F = qvBsinθ, and can now solve for i? Will sinθ be sin90?
Homework Statement
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Suppose the particle has a charge q = 2.5 μC and is moving with a velocity of magnitude v = 1.0 × 103 m s−1, in a direction parallel to the wire and in the same direction as the current. The particle is at distance d = 1.5 mm from the wire and experiences a force of...