Recent content by caprija

I know it's not the quadratic formula, I was just asking. I figured out the height, it's 21.2 and the answer to the question is 4 sec. but I don't know how to get it.

The height h of the ball is given be h = 1.2 + 20t -5t^2, where t is in seconds. If the ball is caught at the same height at which it was hit, how long is it in the air? How do I figure out the time? quadratic function? -b/2a?

Alright, Thank you.

I'm stuck on how to do this problem My attempt: the answer to the second one is 3x + 2/(x+2)(x-2) Can someone point out my mistake?

Ok so the solution would be: (x + 2) ^2 - 4x x^2 + 4x - 4X + 4 answer: x^2 + 4

If f(x)=x^2 - 4x, determine an expression for g(x) g(x) = f(x + 2) How would I substitute f(x) when they are separated? my attempt g(x) = x^2 - 4x (x + 2)

Thank u :)

never mind i got it :)

Well thanks for responses guys! Ki Man - I plan to do something in biology.

I've basically just finished grade 10 physics, I didn't find it all that hard. The problem also was that me and some of my classmates felt the teacher wasn't teaching that well, which made it a little harder to understand. Basically my questions is should I take it in grade 11, even though...

Does warm water rise or fall in cold weather? I think it falls Does it have to do with convection??

Thanks so much!

I thought it was together :blushing: So if it was let's say carbonate (CO3) there would be 1 carbon and 3 oxygens right?

yes...

how though? there are 3 NH on one side and 4 NH on the other.