Recent content by Cardinality

For problem: See Attachment I've never done a problem of this sort and it's proving to be much more difficult compared to the other problems I have had assigned to me. I'm not entirely sure which formulas to use but I've been playing with the following: Length of Arc = r\theta A = \pir^2 C =...

Ahh, I see it! Thank you...makes my method seem very tedious So y'/y = 1/cos or sec :-p

So would I have two separate solutions? i.e: One for when the denominator is positive and the other for when it is negative, and then simplify from there? Or is it something else? Thanks! I have the absolute value in the denominator so far, I guess it serves as a general answer. If what...

Not sure, but I have two guesses: a). What catches my eye first are the (secx + tanx)^2 in the numerator and denominator. But, I don't know anyway to simplify the expression further. b). A possible trigonometric identity I don't see? Haha, give me a hint! :P

Yes I have that answer exactly! (I simplified by factoring out the secx to get (secx)((secx + tanx)^2) in the numerator) Sorry, I realized my input into WolframAlpha was incorrect. Thanks for your help!

I see my error! The numerator is now correct. But I have two of these ((sec(x)+tan(x))2)1/2=|sec(x)+tan(x)| expressions in the denominator, and the answer has only one. How would I go about handling this?

Problem: y = ln|sec(x) + tan(x)| Attempted Solution: See Attachment I was hoping someone could identify my error and possibly write it out for me. At first I thought my steps were correct and everything was in order. However, when I checked my answer on WolframAlpha it gave me a slightly...

Two things: 1). I'm an idiot. 2). I love you guys, thank you. Did I mention I'm an idiot? Note to self: Move your *** from your desk from time to time and get a breather...or you forget to factor :bugeye: Thanks again, & good night friends! :zzz:

Edit: Yeah I'm just going to hope you didn't see this post...my god, that was horrible. LOL

Factor out from where? The main body so it's the numerator to (1-y)? Where would I go from there?

I posted my work in the previous post please take a look!

Oh ok. Here are my attempts at the solution (see attachments). The attachments are two separate work-in-progress solutions with slightly varying steps. If someone could please help me out that'd be great. This assignment is due tomorrow morning at 8 for me (it's almost midnight right now)...

Thank you for the replies. I double checked, and this is the expression I was given. Checking this expression on wolframalpha you get the answer of 1/2. http://www.wolframalpha.com/input/?i=lim+%28x--%3E1%29+%283%2F%281-x%5E%281%2F2%29%29+-+2%2F%281-x%5E%281%2F3%29%29%29 If however, the...

Thanks Ray, but I unfortunately do not know how to expand. If there is another method, please suggest so! LCKurtz, think you could help? Sorta stealing my thread here aha

I'm sorry, I don't think I quite understand Ray Vickson. If anyone is willing to explain their method a little more in-depth it would be greatly appreciated!