Recent content by cataschok

thank you kind sir, you have saved me many hours of frustration!

Homework Statement use product rule to find the derivative of g(x)=(2x+1)^2(x-7)^3 Homework Equations i've applied chain rule and product rule to get... The Attempt at a Solution 4(2x+1)(x-7)^3+3(2x+1)^2(x-7)^2 i need to factor out to get the following.. 5(x-7)^2(2x-5)(2x+1)...

To be honest, it'll help if you can explain to me a little more lol

I'm approaching 0 solutions atm. lol but I had a last try \sqrt{(ax+b)} - 2 = x ... \sqrt{(ax+b)} = x + 2 ax + 4 = (x+2)^2 ax + 4 = x^2 + 4x + 4 ax = x ( x + 4 ) cancel out the x's a = x+ 4 if lim x->0, a = 4

yes the equation that you wrote is correct from what i got in the book, it says when both the numerator and denominator approaches zero, the best way to go at it would be to simplify the the quotient. So I multiplied top and bottom with \sqrt{}(ax+b) + 2 the numerator will eventually...

Homework Statement Find numbers a and b such that lim x\rightarrow0 [\sqrt{}(ax+b) - 2] / x = 1 The Attempt at a Solution so far, I've gotten to ax+b = (x+2)^2 ... lim ax+b - lim (x+2)^2 = 0 ...b - lim (x+2)^2 = 0 ...b = 2^2 ...b = 4 If i try to place b=4 back into the original...