What is the Factored Form of the Derivative Using Product Rule?

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The derivative of the function g(x)=(2x+1)^2(x-7)^3 is calculated using the product rule, resulting in the expression 4(2x+1)(x-7)^3 + 3(2x+1)^2(x-7)^2. To factor this expression into its final form, 5(x-7)^2(2x-5)(2x+1), one must first identify common factors and combine terms appropriately. The key steps involve recognizing the common factor (2x+1)(x-7)^2 and simplifying the remaining terms within the brackets.

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Homework Statement


use product rule to find the derivative of g(x)=(2x+1)^2(x-7)^3


Homework Equations


i've applied chain rule and product rule to get...


The Attempt at a Solution


4(2x+1)(x-7)^3+3(2x+1)^2(x-7)^2

i need to factor out to get the following..
5(x-7)^2(2x-5)(2x+1)
That's the final answer from the book. But the steps to get there... I'm lost. Can anyone help me out on getting it to the factored form?
 
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cataschok said:

Homework Statement


use product rule to find the derivative of g(x)=(2x+1)^2(x-7)^3


Homework Equations


i've applied chain rule and product rule to get...


The Attempt at a Solution


4(2x+1)(x-7)^3+3(2x+1)^2(x-7)^2

i need to factor out to get the following..
5(x-7)^2(2x-5)(2x+1)
That's the final answer from the book. But the steps to get there... I'm lost. Can anyone help me out on getting it to the factored form?
Look for factors that are common to both terms.
4(2x+1)(x-7)3+3(2x+1)2(x-7)^2
= (2x+1)(x - 7)2[4(x - 7) + 3(2x + 1)]

Now combine the terms in the brackets and pull out the common factor there, and you'll have what you need.
 
thank you kind sir, you have saved me many hours of frustration!
 

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