Recent content by Chaos_Enlightened

Thank you mastermind01 it was helpful

Yes I mean quadratic (mistake) and I mean that I don't understand where does the √x+√y come from (are we considering the value of (a+√b)^(1/2) as √x +√y?)

Homework Statement The method given in my book is to find the square root of a quadric surds is to : Consider a and b where both are rational and √b is a surd Equate the square root of a+√b to √x+√y ie (a+√b)^(1/2)=√x+√y Squaring both sides we get a=x+y and b=2√xyHomework EquationsThe Attempt...

Thank you Sammy's

Thank You All!

Wait I could just substitute then X^3-6x^2+12x=14+6(2^1/3+2^2/3). ==: x^3-6x^2+12x=14+6x-12. ==: Ans. Is 2

Which one should I factorise

That might just do it

Got x^3-6x^2+12x=14+6(2^1/3+2^2/3)

Ok

Should I go on and find x^3

Homework Statement If x=2+2^1/2+2^2/3. Then x^3-6x^2+6x=? Homework Equations (A+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca+) The Attempt at a Solution x^2= 6+3(2^2/3)+2^4/3+4(2^1/3)[/B]

Thanks for the advice

hilo New here! mainly here for doubts of maths and science of 10th-9th classes Lookin forward to help