Charles Link's latest activity

In that case, one would need additional spectral detail, such as measuring with two or more bands.

I was able to use it to determine the temperature of a calibration blackbody source with known aperture size at close range, ( distance...

I think the problem is more difficult than that- the emissivity can vary wildly over the relevant waveband (especially either MWIR or...

I imagine the surface electron activity in 'cool condensed matter' will be subject to that much more than surfaces of stars at thousands...

Add more cool geology pictures if you have them.

I think it is probably impractical and perhaps almost impossible to use Stefan's law, (which is the power radiated over the complete...

So it's still a single colour analysis except for some special applications? I guess that way is chosen because the 'numbers' allow /...

Perhaps we should include a little more detail. Stefan's law is ## M=\sigma T^4 ## where ## M ## is ## \pi ## times the integral of...

That was a pretty good effort! Thanks. That's the power of PF; we bump into islands of expertise all over the place in these forums. You...

I don't know that I can answer what you are asking, but for a laboratory type blackbody at approximately 1000 degrees Centigrade, one...

or ##RL^2 = (2x)^2 - (2)^2 = 4x^2-4## We can also draw the other diagonal and apply Ptolemy directly: ##2x + 22x =...

@neilparker62 My solution with your diagram is simple. Let RL=red line. Then ## (RL)^2=2^2+4x^2-2(2)(2x) \cos{\theta} ## and ##...

Thanks - just once though! Since one triangle is right, Pythagoras will there suffice.

@neilparker62 Yes, the law of cosines used twice with your diagram solves it. Very good. :)