Recent content by Charles W

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    Solving Momentum and Newton's Law: Ike and Jim's Truck Physics Problem

    Oh, I understand now! Thank you very much for your help :)
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    Solving Momentum and Newton's Law: Ike and Jim's Truck Physics Problem

    Thank you - I can see the logic of splitting it up, but I cannot see how I am able to deduce the value of u from this?
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    Solving Momentum and Newton's Law: Ike and Jim's Truck Physics Problem

    Is 60u and 40u in kg metres per second as well?
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    Solving Momentum and Newton's Law: Ike and Jim's Truck Physics Problem

    So: 60u + 40(u+2) = 800kg metres per second Then I can simplify this to 100u + 40 = 800 kg meters per second Then I'm not sure where to go from here because the units don't seem to work for a subtraction?
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    Solving Momentum and Newton's Law: Ike and Jim's Truck Physics Problem

    I wrote down two expressions: 60u + 40v = 800kg metres per second (using the equation for momentum to work out 800 kg metres per second - (60*8) + (40*8) v = u + 2 metres per second Sorry for not providing enough information, but after this stage I could not think of any other approaches
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    Solving Momentum and Newton's Law: Ike and Jim's Truck Physics Problem

    Homework Statement Ike and Jim are sitting in toy trucks; the masses are 60kg and 40kg respectively. The trucks are moving at 8 metres per second along a track, with Ike's behind Jim's. Ike pushes Jim's truck away with a pole, and Jim moves off 2 metres per second faster than Ike. What is...
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    Why is the central electrode in a G.M. tube positive?

    Thank you very much! I understand now :)
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    Why is the central electrode in a G.M. tube positive?

    Why is the central electrode in a Geiger-Muller tube always positive (and not negative)? Many thanks!
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    Calculate Torque for 8N Forces on 0.6m Beam

    Thank you - that makes sense to me now! :)
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    Calculate Torque for 8N Forces on 0.6m Beam

    So do I multiply my answer by two? 2.07 * 2 ≈ 4.15 Therefore is the correct answer rounded up to Option 2. - 4.2Nm?
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    Calculate Torque for 8N Forces on 0.6m Beam

    Homework Statement Two 8.0N forces act at each end of a beam of length 0.60m. The forces are parallel and act in opposite directions. The angle between the forces and the beam are 60 degrees. What is the torque of the couple exerted on the beam? 1. 2.4Nm 2. 4.2Nm 3. 4.8Nm 4. 9.6Nm Homework...
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    Conservation of Momentum of two trolleys

    Thank you very much Orodruin! I haven't seen that equation before - will definitely come in handy!
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    Conservation of Momentum of two trolleys

    Thanks! So using the equation I used earlier: Rearranging this equation, Velocity = Momentum/Mass Therefore, by my reckoning, velocity = 12/6 = 2 metres per second Using this, can I then use Kinetic Energy = 1/2mv^2, to give a Kinetic Energy of 12J (option 2)? Is that correct?
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    Conservation of Momentum of two trolleys

    Homework Statement There are two trolleys traveling in the same direction which are about to collide. Trolley 1 is traveling at 4 metres per second and has a mass of 2kg The other, Trolley 2, (which is in front) is moving a 1 metre per second and has a mass of 4kg. After the impact, they...
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    Conservation of Momentum and Collisions

    No worries! Thanks for your help :)
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