Recent content by Chocolaty

How do you derive a function where the trig is under a square root like this: y=sqr(tan^-1(x)) y=(tan^-1(x))^(1/2) i know that y=tan^-1u(x) => dy/dx=1/(1+u^2)*du/dx But how do I work it out? The book doesn't give the answers to pair numbers :(

ok. Does anybody know what this term actually means? ln( x y ) There's no plus or minus or whatever.

I'm taking cal 2 right now and i missed the part in cal 1 where he talked about "log theorem". Now this guy tells us that he's lazy when he corrects exams and if we don't use the log theorem to derive a term then he won't correct that term. I've looked on the net but couldn't find explanation or...

nevermind i got it. You need to use the generalized power rule: [u(x)]^n => n*u^(n-1)*u' so tan(3x)^4 => 4*tan(3x)^3*sec^2(3x)(3)

What is the derivative of: tan^4(3x) The teacher wrote 4TAN^3(x) + sec^2(3x)(3) but i think he made a mistake. I know that tan^4(3x) = tan(3x)^4 and that this equals 4tan(3x) in algebra When I derive this i get the following: sec^2(3x)(3) I'm not sure what to do with the coefficient 4...

How do you calculate the mechanical advantage of a 3 gear train system. The formula I have for gears is only for 2 gears: MA = number of teeth in the driving gear/number of teeth in the other gear.

Thanks Fermat, forgive the weird question, I've got a book full of them. Tip to anyone who reads this: "never choose to take distant courses when you can take them at school"

I'm not exactly sure which force you're talking about. I found this formula in my textbook. I scanned the formulas we have for buoyancy, I got it from the one on the right of this page http://img474.imageshack.us/img474/641/buoyancy1rq.jpg We have another formula as well which is not on...

the weight of the liquid displaced

See I've understand that F=1000*9.8*3*15 F=441000N But how do I prove that this is the difference between the upward and downward force?

Hi, I'm not sure how to prove this http://img402.imageshack.us/img402/5367/buoyancyq0wn.jpg I tried developing a bit but I'm stuck, can anyone point me in the right direction please thanks

(6000N + 300N)/8MA = 787.5N So the only thing you have to do is basicly ignore the fixed pully and multiply the MA by 2 for each moveable pulleys in any possible system? This is like childs play... i was complicating things for nothing

How do you work the math dealing with the ceiling in all this? Edit: ok i think i understand what you wrote.

Of course i want to learn, if i have the answer right it means that the calculation is right. I think that the highest pulley is fixed and the 3 others are moveable. So the mechanical advantage is 2*2*2 = 8. But since the 3 moveable pulleys are attached to the ceiling I think it means that...

No, whether my answer is correct. I'm really not sure if i worked the problem correctly.