Recent content by Claire84

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    Moments of Inertia for a right circular solid cone of mass

    Okay but if you'e finding it about rhe base, is that not just finding it about the diameter? Cos that's what we've got to find later using th 2 previous results.
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    Moments of Inertia for a right circular solid cone of mass

    Okay, well thanks for the Pm you sent me. The only issue with that is they use the inertia tensor thing which we haven't really done yet, and they use the m.o.i about the diameter to get what I'm looking for, whereas I have to do it the other way (i.e find m.o.i about line through the vertex...
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    Moments of Inertia for a right circular solid cone of mass

    Hi there, I was hoping that someone here could maybe give me a hand with a couple of issues I'm having to do with moments of inertia. For a right circular solid cone of mass m, height h and base radius a, we have to show that its moment of inertia about a line through its vertex and...
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    A few problems with the operator method .

    I'd do the last eqt I mentioned by multiplying through by x^2 so we'd have 0(0-1)y - 2x^20y + 2nyx^2 where 0=xD. Then rearranging it to get it into the form that we want, we'd have 0(0-1)y= x^2 (2(0) +2n)y. Sorry I can't make it any clearer. Someday I will learn how to type mathemtical...
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    A few problems with the operator method .

    y''-2xy'+2ny=0 is what seems to be given evereywhere else for the Hermiet eqt btw, which is fine to solve by this method...
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    A few problems with the operator method .

    I'd do that but I don't know what I'm supposed to get in the end. I mean the others were simple but I just don't know how you're supposed to work with this one. Hopefully there is an error with this one. I can always badger the poor lecturer about iton Monday after class. It's no wonder the...
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    A few problems with the operator method .

    No problem. We have D = d/dx and that symbol that you stated is xD (just x times d/dx). Sorry, I should have stated it.
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    A few problems with the operator method .

    Btw, I was at the library this afternoon for about an hour and I checked through all their differential equation books, and none of them had the Hermite eqt as this. They all had the same one and it wasn't this so do you think it's possible there has been a misprint here?
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    A few problems with the operator method .

    A few problems with the operator method... Hey there, I've just started doing the operator method etc in Maths and I was hoping someone could give me a hand here cos I've got a couple of qs (relating to the homework sheet)...
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    Question about Complex Integrals

    Okay, well this is what I've got so far from using the Laurent series (although I don't imagine it's right since I'm not too good at it!). I've got the first 4 terms of the Talyer expansion to be 1+ 2iz - 2z^2 - (4/3)iz^3 So putting this back into what we had originally we get (-2i)/z +...
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    Question about Complex Integrals

    When I'm getting the Laurent series for this, do I expand e^(i2z) using the Talyler series? Well, the Maclaurin series really since z=0?
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    Question about Complex Integrals

    Oh, and we've to show that it is equal to pi. :smile:
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    Question about Complex Integrals

    Decided just to write it up on word anyway so here's my working out (hope it appears!)
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    Question about Complex Integrals

    Speaking of integrals, I was hopign someone could give me a hint as to what I've to do to get the integral between 0 and + infinity of (sin^2x)/(x^2). I can integrate the same thing just without the squares in it by doing the whole method of using a semicircle with a little arch in the middle...
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    Question about Complex Integrals

    I handed it in with the more simple way so *fingers crossed* it comes out okay. I asked the lecturer the day before I was to hand it into see if he could give me a bit of feedback on how tight the bound had to be, but he just told me that I was the mathmatician and what did I think... not...
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