Recent content by cm846

Thats ok. I got the 1.755 for the Req for the entire circuit: (R2) 1/5 + (R4) 1/10 = 1/Req which is 3.33 then I added R3. 11 + 3.33 = 14.33 then 1/14.33 + (R1) 1/2 = 1/Req which is 1.755.

3.99 is the answer to the question "What is the current supplied by the battery?" so I guess I'm not sure how I'd find it any other way than the way I showed?

I just took the 7V divided by the Req of 1.755 to get 3.988

Homework Statement R1 = 2 Ω R2 = 5 Ω R3 = 11 Ω R4 = 10 Ω V = 7 V What is the current through R2? Homework Equations Req for parallel resistors: 1/Req = 1/R1 + 1/R2... Req for series resitors: Req = R1 + R2... Electric potential V = current I x resistance R I have found...