(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

R1 = 2 Ω R2 = 5 Ω R3 = 11 Ω R4 = 10 Ω V = 7 V

What is the current through R2?

2. Relevant equations

Req for parallel resistors: 1/Req = 1/R1 + 1/R2...

Req for series resitors: Req = R1 + R2...

Electric potential V = current I x resistance R

I have found that Req is 1.755 and the current supplied by the battery is 3.988.

3. The attempt at a solution

I tried taking the 3.988 x 3.33 (the Req for R2 and R4) which is 13.29V and since the voltage drop is the same for parallel resistors I then divided by the 5 ohms to get 2.658 amps but that's not right.

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# Finding current with parallel resistors

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