1. The problem statement, all variables and given/known data R1 = 2 Ω R2 = 5 Ω R3 = 11 Ω R4 = 10 Ω V = 7 V What is the current through R2? 2. Relevant equations Req for parallel resistors: 1/Req = 1/R1 + 1/R2... Req for series resitors: Req = R1 + R2... Electric potential V = current I x resistance R I have found that Req is 1.755 and the current supplied by the battery is 3.988. 3. The attempt at a solution I tried taking the 3.988 x 3.33 (the Req for R2 and R4) which is 13.29V and since the voltage drop is the same for parallel resistors I then divided by the 5 ohms to get 2.658 amps but that's not right.