That's even nicer, I wonder why they use the (1 - V / U)-1 in the lecture? Probably works out easier to apply or something, I'm sure I'll find out when I watch the rest of it.
Thanks again!
Wow I'm stupid, thanks for putting up with me. I finally got there I think -
ΔTo - VΔTo / U = ΔTs
ΔTo( 1 - V / U ) = ΔTs
ΔTo / ΔTs ( 1 - V / U ) = 1
ΔTo / ΔTs = 1 / ( 1 - V / U )
ΔTo / ΔTs = (1 - V / U )-1
Sorry that was a mistake I forgot to divide the ΔTs by ΔTo. Now I've gotten this far but still end up with the variables on both sides
ΔTo = ΔTs + VΔTo / U
ΔTo = ΔTs / ΔTo + V / U
ΔTo / ΔTs = 1 / ΔTo + V/U / ΔTs
ΔTo / ΔTs = 1 / ΔTo + V / UΔTs
Homework Statement
I'm watching this lecture and wanted to attempt to derive the expression for ΔTo/ΔTs
Homework Equations
ΔTo = ΔTs + VΔTo / U
The Attempt at a Solution
I have worked out that ΔTs = 1-V / U, however I'm stuck trying to get ΔTs / ΔTo because of the ΔTo on both sides of the...
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