Recent content by curto

cheers

ahh i see, first equation gives 10.5cm for f. that was simple, why didnt i see that before?? now i was thinking we just use the thin lens equation in the first place since all it was doing is the same thing a thin lens would do, but i wasnt sure because i don't fully understand what's going on...

Homework Statement A zone plate is to be set up on an optical bench, where it will be used as an enlarging lens. Its innermost zone is to be 0.2250 mm in diameter and monochromatic blue-green light of wavelength 480 nm from a cadmium arc is to be used. If the magnitude of the enlargements is...

i figured it out but just for anyone else who would like to know, its actually quite simple. the potential U(x) is equal to the integral of -F dx. simply find an expression for F (remember F = ma = m d^2x/dt^2) and then integrate. that's going to be your expression for U(x). then all you got to...

Homework Statement my spreadsheet: (oh and please ignore the fact that I've got my amplitude set to 39, i was still answering question 1 when i took the screen shot) the question i am currently having problems with is question 2: Homework Equations i know the potential is...

thanks heaps! it all makes sense now, cheers

so the latent heat for 1kg of lead.. has the units J per nothing and the specific heat of lead has the units J per 1kg. that's why I am getting confused if you can see what i mean. density is defined to be the mass per unit of volume. so we have p = m/V hence V = m/p but we don't know the mass...

i see how those units are going to cancel, and I am going to accept that we can just change the specific latent heat into the latent heat by just multiplying it by 1(units of the denominator) .. ? and so i guess I am back to the initial problem which is how to find deltaV? thanks for the help so...

i still don't understand how the latent heat can be used to find volume if we have density. the units arent even going to cancel unless i add some other factor into the conversion. i can get numbers in terms of m^3 per J.. but that's not volume.

oh ok (btw i meant 10^5 for 1atm not 10^6 lol, sorry). so to find volume from the latent heat and density.. i need to? sorry I've never found volume from density and latent heat before. i haven't really had to use latent heat much at all so I am not very familiar with how to use it sorry. could...

ΔV i assumed would just be the difference between my two volumes, which i found to be 0.971m^3 and 0.939m^3 by dividing the densities by the density of lead which is 11340kg/m^3. and yeah so my ΔV was just 0.032m^3

Homework Statement Homework Equations use clausius-clapeyron equation: \frac{dp}{dt} = \frac{L}{T(V_{2}-V_{1})} which can be rearranged (i think) in the following: p = p_{0}+\frac{L}{\Delta V}ln(\frac{T}{T_{0}}) The Attempt at a Solution so using the above equation i solved...

I don't completely understand but if you're saying that assuming \DeltaP ~ P is okay then that's good enough for me. We've been getting heaps of these dodgy questions lately and they're starting to annoy me lol. Thanks.

Homework Statement A neutron in an atomic nucleus is bound to other neutrons and protons in the nucleus by the strong nuclear force when it comes within about 1 fm of another particle . What is the approximate kinetic energy in MeV of a neutron that is localised to within such a region? Take...

ahh ok thanks a lot mate, that's explained a fair bit. i wish i knew about this site when i was in high school lol, its pretty damn useful. cheers