- #1

curto

- 20

- 0

## Homework Statement

## Homework Equations

use clausius-clapeyron equation: [itex]\frac{dp}{dt}[/itex] = [itex]\frac{L}{T(V_{2}-V_{1})}[/itex]

which can be rearranged (i think) in the following: [itex]p = p_{0}+\frac{L}{\Delta V}ln(\frac{T}{T_{0}})[/itex]

## The Attempt at a Solution

so using the above equation i solved for T in which i got: [itex]T = T_{0}e^\frac{(P-P_{0})\Delta V}{L}[/itex]

and then since density is equal to mass per unit volume i solved for V and got my two volumes by dividing the densities given by 11340. also 1 atm is roughly 10^6 pa so i used that and got a massive answer for T which is obviously wrong. then i just tried doing it in terms of atm in which i got a very small increase in temperature. isn't the melting point meant to become lower if the pressure is increased?? so how can T_{0} times e^{whatever} equal a number less than T_{0}?? does that mean my formula is wrong?