Recent content by dahoom102

Oh, i just realized! how couldn't I be logical in the first place ;(. Thanks a ton haruspex!

Hi I've tried solving this question but it seems that I flipped the direction of the impulse, what did I interpret wrong? the question didn't give any clue on their direction before so I couldn't infer the direction of the impulse. It also just gave me the magnitude without the direction. I...

Ohhhhh i see now! Thanks a ton PeroK for your time!

Ok but i am still unable to grasp how is this going to help mg=kx x=98/400=0.245m

It is the point at which a body exhibiting SHM oscillates between

It came in a simple harmonic motion quiz so it should be relevant i guess also its about a spring and amplitude

Hi, I have no idea what formula to use while given these values, basically, it fits no formula. Any thing could help? Many thanks in advance Correct answer is 65

oh my mistake I didn't notice thanks a lot!

The answer here is A What i did is getting the area as follows, 2×4×1/2 +3×-6×1/2 +4×-6 = -29 and then use this Δω=ωf-ωi -29=ωf-5 ωf=24 but there is no such choice.

Thank you! That's quite helpful.

i attempted this problem by using conservation of energy, mgh=1/2kx^2 mgD=1/2kD^2 2mg=kD k=2mg/D why is it wrong ? btw the correct answer used mg = kx which is mg/D