Getting the angular velocity using the angular acceleration graph

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SUMMARY

The discussion focuses on calculating angular velocity from an angular acceleration graph using the area under the curve. The area was computed as -29, leading to the equation Δω = ωf - ωi, resulting in ωf = 24. However, the user noted a discrepancy as this value did not match any provided choices. The relevant equation α = dω/dθ was also mentioned, emphasizing the relationship between angular acceleration and angular velocity.

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dahoom102
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Homework Statement
The graph below shows a plot of angular acceleration in rad/s2 from t=0 to t = 8s, the angular velocity at t=0 is 5rad/s ccw. the angular velocity at t=8 is
Relevant Equations
α=dω/dθ
1612806379741.png

1612806406863.png

The answer here is A
What i did is getting the area as follows,
2×4×1/2 +3×-6×1/2 +4×-6 = -29
and then use this
Δω=ωf-ωi
-29=ωf-5
ωf=24
but there is no such choice.
 
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Why 4x-6 (in your language) ?
 
BvU said:
Why 4x-6 (in your language) ?
oh my mistake I didn't notice thanks a lot!
 
dahoom102 said:
Relevant Equations:: α=dω/dθ
##\alpha = \dfrac{d\omega}{dt}=\omega \dfrac{d\omega}{d \theta} .~~## :oldsmile:
 
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