Recent content by danielsmith123123

My answer for this question is d as every car has the same result for the force of friction since the normal and coefficient of static friction is the same. I cannot find an answer online so can anyone help verify this? Thank you.

Thank you

Finding x by force formula - only force acting is gravity ma/-k = x (0.2)(-9.8)/185 = x 0.010594594 = x Finding x by wd formula WD_ spring = (1/2)kx^2 F x = (1/2)kx^2 2(mg)/k = x [2(0.2)(-9.8)]/ 185 = x 0.021189189 = x how come the work done and force formulas produce different values for x...

Ok thank you, i edited the forum. I guess you can't open pictures on this website, but i calculated d with Vf^2=Vi^2 +(2)(a)(d) 0^2 = 15^2 + (2)(-9.8)d d = 11.4m (I realize i probably shouldn't use "x" and "d" interchangibly)

Is the answer key wrong? I keep getting the same answer and it is verified with the freefall equation distance=1/2 (g)(t^2)

Ok, thank you

I am just confused on how to find the normal force/ FN of the first object. My classmates are saying Fgy is the exact same as Fn but I don’t get why Fgy= Fg sin theta Fgy= (20)(9.81) (sin35) Fgy= 112.5 Fgy = FN

Oh ok, thank you for all your help

I think the y axis. If it was the negative x-axis wouldn't it be [Left 65 Up]

"Determine the net force"

1. break down 430N [Up 35* L] into components 430 cos 35 = 352.2N [L] 430 sin 35 = 246.6N 2. ΣFx= 352.2N [L] ΣFy= 246.6N + 280N - 430N ΣFy = 86.6 3. Pythagorean theorem with the two will give you a magnitude of 362.7N Then using tan you can find the angle of [L 76 U] This method was...

Nevermind I found what I had to do, thank you though.

Sir, if you looked at the picture I sent you: - You would've saw my vectors; I added two opposite vectors meaning I changed the 2.78W into -2.78E . I did that to simply save space and time. - I also did (6.25)(cos40) = 4.788 and I am not sure if you're telling me not to round from 4.787777769...

Yes I figured it out I wasn't using my common sense, thank you

I didn't reverse it, I simply copied both down wrong I'll show you my work