My professor had accidentally made a typo when writing the problem (on a test from a previous course). He typically tends to make things very realistic which is why I was surprised by the result. Thank you for the responses. I just took my exam, definitely aced it.
Whoops...that last post calculated the maximum height reached, not the height at which the little bugger started from. I'm not really sure why I couldn't use 2.5s as the time like I did before.
Hmmm, I still seem to be getting the same answer.
Using:
v_y = v_0_y - gt
0 = 0.9398 - (9.8)t
I found that it takes roughly 0.06 seconds for the frog to reach the highest point in the jump leaving 2.4 seconds of freefall.
y = y_0 + v_0_yt - (1/2)gt^2
0 = y_0 +...
[SOLVED] Projectile Motion Problem
Homework Statement
A frog jumps from a log and lands on the ground a distance of 2.80 m away. The frog is airborne for 2.5 seconds, and leaves the log at an angle of 40 degrees. (a) What was the frog's speed (vo) just after it jumped? (b) How high above...