Recent content by Delta

The 968N comes from a combination of gravitational acceleration and the acceleration of the elevator.

Not quite. Remember the relationship between velocity, time and distance?

Are you sure about this transition?

Looks good to me, but don't forget the units, and you need to note the direction of the force as well as the magnitude.

Not yet, you've so far got the horizontal velocity (30.02). We're on to finding the time it takes to travel 20.0m (horizontally). Then we can start on the vertical components.

Energy is always conserved, so if there PE=0 at the bottom of the run, what is the KE? Have another a look at your 5th and 6th answers for a clue.

It's because the question is asking for his weight not his mass. If you can work out his "mass", your can work out his weight.

Try sketching down the outputs you want in order, starting with -5V, 0V (ground), 5V and 10V. How many gaps are there between the nodes?

Maybe the situation has arose from them not liking the sandwich I am eating in front of them.

Try moving the left resistor above the middle resistor, and the right resistor at the bottom. Keep the wires connected as they are, and see what the circuit looks like.

Bit of a find this, might get one myself. The left and right channels go to pins 11 and 12 as you say. The third will connect to the grounds on 10 and 13. Don't need to worry about current if you're staying within the voltages limits. Just connect straight to it. But also add a cap to...

I was thinking star-delta transformations, but I've just moved them around again and the circuit is simpler than I though ... doh! Where do you get 5R from?

Are you familar with transformations with resistor/impedance networks? This looks to be be one of those. I recommend drawing the circuit another way.

For typical LED's, it would be impractical to create a supply just enough to power the LED, remembering an LED is a discrete device. You would be hovering around a critical area of the LED's characteristic curve. There will already be variations in the LED's performance due to manufactruing...

Are you connecting more than one LED? If not you just take the LED voltage from the supply voltage and divide it by what current you want to use. Say, for example, you want to power a 1.5V LED at 30mA from a 9V supply. The resistor value would be (9V - 1.5V) / 30mA = 250ohms. The power...