Integration (displacement or position)

Click For Summary
SUMMARY

The discussion centers on the integration of the equation derived from Newton's second law, specifically the equation mg - u - kv = m*a, where m = 3000 kg, g = 10 m/s², u = 172000 N, and k = 30. The user seeks assistance with integrating the left side of the equation, ultimately leading to the expression (142000 + 30v)/v * dv = -1/3000 * ds. The user has two scenarios to evaluate: when s = 0 and v = 1000, and aims to find the displacement s when v = 0 after integration.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Proficiency in calculus, specifically integration techniques
  • Familiarity with variable acceleration and its implications
  • Knowledge of physical constants and their application in mechanics
NEXT STEPS
  • Study integration techniques for variable acceleration scenarios
  • Learn about the application of initial conditions in solving differential equations
  • Explore the concept of displacement in physics and its mathematical representation
  • Review examples of integrating functions involving rational expressions
USEFUL FOR

Students studying physics or engineering, particularly those focusing on dynamics and mechanics, as well as anyone needing to solve differential equations related to motion.

kieran1black2
Messages
23
Reaction score
0

Homework Statement


the trouble is in the integration on the left side (go straight o my answer down the bottom of the page)... please help me...

mg-u-kv=m*a

where (all constant)
m= mass= 3000
g=gravity=10
u=thrust=172000
k=30

v=velocity=variable
a=acceleration=variable


Homework Equations



accel=v*dv/ds=dv/dt=a

The Attempt at a Solution



30000-172000-30v = 3000*v*dv/ds
-142000-30v = 3000*v*dv/ds
-(142000+30v) = 3000*v*dv/ds
142000+30v = -3000*v*dv/ds
(142000+30v)/v*dv = -3000*ds
v/(142000+30v)*dv = -1/3000*ds

and then integrate both sides, this is where my calculus stops

i know the right side (-1/3000*ds) becomes -1/3000s + c
where
s= displacement or position and
c= constant
i have 2 scenarios

when s=0, v=1000
and what i need to find is when v=0 what is s?


so once i integrate the left side i sub those values in.
 
Physics news on Phys.org
kieran1black2 said:
(142000+30v)/v*dv = -3000*ds
v/(142000+30v)*dv = -1/3000*ds

Are you sure about this transition?
 
if you think you can do it without that transition... go for it... that's just how i interpreted the question
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 27 ·
Replies
27
Views
1K
Replies
14
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 10 ·
Replies
10
Views
3K