Recent content by Demystifier

An answer at a level of popular physics. Because our theory of gravity, called general relativity, says that gravity is not merely something that takes place in space and time, but something that describes the properties of space and time themselves. In particular, in the center of the black...

No, that's not the definition of the computable number. Sure, all computable numbers have this property, but the converse is not true: it is not true that all numbers with that property are computable. In fact, by your diagonal argument you proved just that. If you take the definition from...

https://en.wikipedia.org/wiki/Map%E2%80%93territory_relation

The map is not the territory. But Tegmark assumes that it is, and then develops this assumption to its logical conclusion. For me, it's a nice reductio ad absurdum.

Yes, but the field cannot be something that removes all the conceptual problems of NRQM. First, in NRQM the position is an observable, while in QFT the fermionic field cannot be an observable, because it's not a self-adjoint operator. One can argue that an observable does not need to be a...

Since you are interested in foundational topics, such as MWI, I highly recommend Norsen: https://www.amazon.com/Foundations-Quantum-Mechanics-Exploration-Undergraduate/dp/3319658662?tag=pfamazon01-20

Gibbs and Boltzmann entropy are not the same, but in thermal equilibrium they have the same value. For some foundational, philosophical and ontological aspect of statistical mechanics take a look at my https://arxiv.org/abs/2308.10500 and references therein.

All.

Even without AdS/CFT correspondence, QFT is obtained from string theory as an approximation, in the limit in which wavelength is much larger than the string length.

Nope.

It depends on what you mean by RQM. If by RQM you mean Bjorken & Drell 1, then yes, you can obtain it from Bjorken & Drell 2. But in Bjorken & Drell 1, there is no probability density of particle positions. So how do you obtain probability density of particle positions in NRQM? My answer is the...

Yes, but it can also be transformed to the Schrodinger picture, and obtain two Schrodinger's equations for the quantum states.

The non-relativistic limit of relativistic QFT is non-relativistic QFT. Non-relativistic QFT, also known as "second quantization", is widely used in condensed matter physics. In general, states in non-relativistic QFT do not have a definite number of particles. However, when non-relativistic QFT...

Indeed, not only that I think that emergent relativity resolves the conceptual problems of quantum foundations, but also the conceptual problems related to semiclassical and quantum gravity, such as the problem of time in quantum gravity, the cosmological constant problem and the black hole...

There is such a formulation, but it is very complicated. https://arxiv.org/abs/1410.3676