Recent content by Demystifier
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Today I Learned
Today I learned that Terry Rudolph, the R from the famous PBR theorem, is a grandson of Erwin Schrodinger and his mistress. https://en.wikipedia.org/wiki/Terry_Rudolph- Demystifier
- Post #6,911
- Forum: Fun, Photos and Games
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Undergrad On computing quantum waves exactly from classical action
I have not studied the papers in detail, but at a first look the critique looks much more plausible.- Demystifier
- Post #7
- Forum: Quantum Interpretations and Foundations
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Graduate Why is 0 K unattainable?
If the Hamiltonian has a continuous spectrum, then, in the canonical ensemble with non-zero temperature, any given energy has non-zero probability density, but zero probability.- Demystifier
- Post #16
- Forum: Thermodynamics
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Graduate Why is 0 K unattainable?
You are right that any state with definite energy has zero probability in that sense. But there is nothing wrong with that conclusion. We are talking about thermal equilibrium, i.e. thermal states in a canonical ensemble, while states with definite non-zero energy are not thermal states, so in...- Demystifier
- Post #14
- Forum: Thermodynamics
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Graduate Six Textbook Mistakes in Quantum Field Theory
I think there were a few, but I can find only this one: https://www.physicsforums.com/threads/quantum-mechanics-myths-and-facts.143045/- Demystifier
- Post #6
- Forum: Quantum Physics
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Graduate Six Textbook Mistakes in Quantum Field Theory
I joined this forum soon after writing this paper, so this is how I have chosen my name. :smile:- Demystifier
- Post #4
- Forum: Quantum Physics
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Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?
Under a coordinate transformation ##x^{\mu}\to x'^{\mu}=f^{\mu}(x)##, the two metrics transform as $$g'^{\alpha\beta}=\frac{\partial x'^{\alpha}}{\partial x^{\mu}} \frac{\partial x'^{\beta}}{\partial x^{\nu}} g^{\mu\nu}$$ $$\bar{g}'^{\alpha\beta}=\frac{\partial x'^{\alpha}}{\partial x^{\mu}}...- Demystifier
- Post #68
- Forum: Special and General Relativity
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Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?
How did you verify this? They do transform as tensors under coordinate transformations, but their indices are not raised and lowered in the usual way. Which is understandable, because when you have two metrics, there is an ambiguity should one raise the indices with ##g^{\mu\nu}## or...- Demystifier
- Post #66
- Forum: Special and General Relativity
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Undergrad Hawking radiation may smooth black hole singularities
Is this something like a white hole?- Demystifier
- Post #8
- Forum: Beyond the Standard Models
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Undergrad Hawking radiation may smooth black hole singularities
My confusion stems from the following. The Bardeen metric significantly deviates from the Schwarzschild only for small ##r##, close to ##r=0##. And yet, global properties significantly deviate from the Schwarzschild even for larger ##r##, e.g. close to ##r=2M##. How to understand that? What do I...- Demystifier
- Post #6
- Forum: Beyond the Standard Models
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Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?
I believe there is no such quantity, because you study a variation of the object that defines the covariant and contravariant components.- Demystifier
- Post #64
- Forum: Special and General Relativity
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Undergrad Hawking radiation may smooth black hole singularities
Does it shed some light on the information paradox?- Demystifier
- Post #4
- Forum: Beyond the Standard Models
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High School Seemingly odd quantum tunneling
That's because tunneling is a consequence of superposition. For example, suppose that at time ##t## the particle can tunnel from the left to the right, through a barrier in the middle. This means that the wave function at ##t## is nonzero both at the left and at the right, i.e. the wave...- Demystifier
- Post #26
- Forum: Quantum Physics
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Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?
3. is just a definition of the dual tensor, i.e. the rule how to raise indices in the same world. In 2. you try to compare quantities from two different worlds.- Demystifier
- Post #62
- Forum: Special and General Relativity
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High School Seemingly odd quantum tunneling
No, the number of degrees of freedom is not directly related to the size of the system. It is more directly related to the number of particles. See also https://en.wikipedia.org/wiki/Degrees_of_freedom_(mechanics)- Demystifier
- Post #24
- Forum: Quantum Physics