Recent content by dgamma3

Thank you Mark!

Yes I can do that. But I do not understand how do integrate (what word do I use?) ∫di(t)/i(t)

I understand how to integrate this: ∫y2dy. I don't understand how to integrate this: di(t)/dt = i(t)p(t) intergrate((di(t)/dt/i(t))*dt = p(t)dt) (see this image: http://i.imgur.com/OdKI309.png) how do you perform the intergral on the left, seeing as as it not dt, but di(t)? thanks

Hello, my textbook states that "Circuits that contain capacitors and/or inductors have memory". In what sense do they have memory? my understanding of memory, is retaining value. how do inductors/capacitors retain value? thanks daniel

If I pinch hold a book, with 6N on either side why is there only one force, of 6 Newton on the free body diagram? for example, the book has this free body diagram. http://i.imgur.com/pwtFZB6.png there are two forces applied to each side of the book. so why is it, than in the free body diagram...

here is a geometric proof, similar to the one in my textbook (copied from Aryabhata, from http://math.stackexchange.com/questions/15294/why-is-the-area-under-a-curve-the-integral) : Is this saying: that the A' equals the function. Which is implying, that the integration of A equals F (where F...

sorry mate. Prove that the square of any integer, when divided by 3, leaves remainder 0 or 1 but never 2. thanks

Homework Statement I know you could prove this by stating every integer is either 3m, 3m+1 or 3m+2. However I am trying to prove this just using either even numbers or odd numbers. so for example, when I try: (2x+1)^2 = 4x^2 + 4x + 1 - expand = 3x^2 + x^2 + 3x + x + 1 - group like...

Homework Statement Ok, So I've tried to prove this statement unsuccessfully. how would you guys do it? (assume [] means floor) [x-1][x+1]+1 = ([x])^2

hello, I am trying to solve this problem: If w is an even integer, then w^2 - 1 is not a prime number. my current working. prove by contradiction If w is a even integer then w^2 -1 is a prime number. if w = 2x then w^{2} -1 = 4x^{2} -1 I am not sure where to go from here, maybe congruence...

is this true or false: If a|b and a|c, then one (or both) of b|c or c|b holds. if I want to disprove this, can I: let a = 5, x = 2 and y = 3. b=ax c=ay then c=bz and c = bg doesn't hold.