Recent content by dkajsdk

I found the x and y components of the tension with the angle. Since acceleration is horizontal and not vertical, only the x component is considered. I used Newton's 2nd Law, 7cos25=ma, and when I solved for a, I got 2.11m/s^2. This is only for mass M (the one without friction). Was I supposed to...

no

An analysis that comes to mind is pulling a sled with a child on it...except there is no incline

Since there is friction, block m is not moving. Only M is moving.?

Homework Statement A block of mass m = 0.500 kg rests on top of a block of mass M = 2.50 kg which is on the floor. A string attached to the block of mass M is pulled so that its tension is T = 7.00 N at a 25.0o angle to the horizontal as shown. The blocks move together across the horizontal...