First i find PE with:
PE=Volts x charge
plug in to:
velocity=[(-2/mass) x PE]^(1/2)
seems right...
PE= 250V / 1.6 x 10^-19 C = 1.56 x 10^21 J
plug in:
and you get velocity at 3.54 x 10^23 cm/s
but when you use that number in the final radius equation, its not = to 1.77 cm (and i know...
Pe
First i find PE with:
PE=Volts x charge
plug in to:
velocity=[(-2/mass) x PE]^(1/2)
seems right...
PE= 250V / 1.6 x 10^-19 C = 1.56 x 10^21 J
plug in:
and you get velocity at 3.54 x 10^23 cm/s
but when you use that number in the final radius equation, its not = to...
Homework Statement
An ion is accelerated through potential diff. of 250 V, directly perpendicular to mag. field.
Find radius of the path of the ion in the field.
Given:
mass (m)=2.5 x 10^-26
charge(q)= 1.6 x 10^-19
Volts= 250 V
Mag. Field (B) = 0.50 T
Homework Equations...