Finding Velocity of Positive ion with Volts given.

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Homework Help Overview

The discussion revolves around finding the radius of the path of a positive ion accelerated through a potential difference of 250 V in a magnetic field. The problem involves concepts from electromagnetism and kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between potential difference and energy, with one suggesting that understanding this definition could aid in using volts to find velocity. Another participant attempts to calculate potential energy and derive velocity from it, but questions the resulting velocity when applied to the radius equation.

Discussion Status

The discussion includes attempts to clarify the use of potential difference in the context of the problem. While one participant expresses confidence in a specific radius value, there is ongoing exploration of the calculations and their implications without reaching a definitive conclusion.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may impose specific methods or reasoning paths that need to be adhered to. There is also a noted discrepancy in calculations that remains unresolved.

dkr1207
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Homework Statement



An ion is accelerated through potential diff. of 250 V, directly perpendicular to mag. field.
Find radius of the path of the ion in the field.

Given:
mass (m)=2.5 x 10^-26
charge(q)= 1.6 x 10^-19
Volts= 250 V
Mag. Field (B) = 0.50 T

Homework Equations



radius= (mass x VELOCITY)/ (charge x B)

The Attempt at a Solution



I know the answer is 1.77 cm for the radius, but i need to prove how, but i can't seem to find an equation or reason to use Volts to get Velocity in the equation.
 
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What's the definition of "potential difference"? Thinking about that should help you figure out how to use the number of volts. Hint: energy.
 
Pe

First i find PE with:

PE=Volts x charge

plug in to:

velocity=[(-2/mass) x PE]^(1/2)

seems right...

PE= 250V / 1.6 x 10^-19 C = 1.56 x 10^21 J

plug in:
and you get velocity at 3.54 x 10^23 cm/s

but when you use that number in the final radius equation, its not = to 1.77 cm (and i know that's right)
 
First i find PE with:

PE=Volts x charge

plug in to:

velocity=[(-2/mass) x PE]^(1/2)

seems right...

PE= 250V / 1.6 x 10^-19 C = 1.56 x 10^21 J

plug in:
and you get velocity at 3.54 x 10^23 cm/s

but when you use that number in the final radius equation, its not = to 1.77 cm (and i know that's right)
 
nvm... its good now, thanks for the help
 

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