Thanks for the fast response.
So, now I have
ω=5.2
centripetal force=(.104)(5.2)^2(.83cos(θ))=2.3cos(θ)
Tcos(θ)=2.3cos(θ) : This is the horizontal component of the tension force equal to the centripetal force
T=2.3
Tsin(θ)=9.8m/s/s*.104kg : This is the vertical component of the tension...
Homework Statement
A 104 g stone is whirled in a horizontal circle on the end of an 83 cm long string. The stone takes 1.2 s to make each complete revolution. Determine the angle that the string makes with the horizontal. Homework Equations
f=ma
v=(2*pi*r)/T
Centripetal acceleration=V^2/rThe...