Recent content by dolpho

If we add br2 / hv to (s)-1,2-dibromobutane. Where would the radical bromine go? The book hints that the product is an optically inactive substance. So I'm guessing that the bromine would go towards the carbon that has the bromine atom on it making 1,2,2-tribromobutane? Would appreciate...

Hmmmm right... So I'm a bit confused on how we take our starting equation and turn it into two. Would we just do y=2t^3 and x = (t/2)^1/3 ?

Hmmmm right... So I'm a bit confused on how we take our starting equation and turn it into two. Would we just do y=2x^3 and x = (y/2)^1/3 ?

Homework Statement Parametrize the curve by a pair of differentiable functions x = x(t), y = y(t) with [x '(t)]2 + [y '(t)]2≠0, then determine the tangent line at the origin. y=2x^3 The Attempt at a Solution Honestly I don't really understand what it's asking for. I assume it wants...

Anyone have any ideas?

So this is what I have so far... .65N=F12 + F32 .65N = (Kq2 / R^2)(q1cos60 + q1sin60 + q3cos60 + q3sin60) Am I on the right track?

Hmmmm...Not quite following you, so in a way we should work backwards? F2= .65 N .65 = F 1 on 2 + F 3 on 2 Is that what you're saying?

Homework Statement Suppose that the magnitude of the net electrostatic force exerted on the point charge q2 in the figure is 0.65 N . (Figure 1) http://imgur.com/4lZliPq Find the distance D. q1 = 2.1 micro C q2 = 6.3 micro C q3 = -.89 micro C Homework Equations F = k |q1|...

Homework Statement Draw the products of the mono-chlorination reaction of methylcyclopentane. Indicate the minor and major products. Homework Equations The Attempt at a Solution I've tried looking up examples of how to do this problem but can't seem to find any. From what I...

Homework Statement Give an acceptable IUPAC name for these compounds. http://i.imgur.com/tHUpwYK.pngThe Attempt at a Solution So the question is really on the 2nd problem in the picture but I need to reference the first one for my question. So my original guess on the 2nd problem was...

Finally! Got it right, thanks so much for your help!

ARG...It's not .8...what the f...heck

Ok I was just thinking that, so its actually. .72 = 1 / Req Req = 1.39? Then we add that to R6 in a series? so 1.39 + 7.6 = 8.99 Now we add R6 to R2 and R1 which are parallel. So... 1/2.2 + 1 + 1/8.99 = 1 / Req = 1.24 = 1 / Req -----> 1 / 1.24 = .8?

nope :( I'm not sure what I'm doing wrong

Ahhh I'm sorry I did a typo. I meant parallel