Recent content by donking225

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    How Do You Calculate the Components of Vector C?

    1. Vector A has x and y components of −20 cm and 19 cm, respectively; vector B has x and y components of 11.1 cm and −20 cm, respectively. If A−B +3 C = 0, what are the x and y components of vector C ? 2. Not too sure. I am thinking that using trigonometry or Pythagorean theorem. 3. I...
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    Motion of an object dropped from a descending and ascending helicopter

    Thanks, looks like I missed the obvious. I got the correct answer now.
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    Motion of an object dropped from a descending and ascending helicopter

    Thanks for the help, I've got c) correct but am still confused about b).
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    Motion of an object dropped from a descending and ascending helicopter

    would this equation be appropriate for b) s=vi*t+1/2*at2
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    Motion of an object dropped from a descending and ascending helicopter

    [b]1. a) A small mail bag is released from a helicopter that is descending steadily at 3.34 m/s. After 2.95 s, what is the speed of the mailbag? The acceleration of gravity is 9.8 m/s2 . Answer in units of m/s b) After the mailbag is dropped, the helicopter continues descending for 1 s but...
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    Find acceleration given initial and final velocity, and displacement

    That's what I thought too, I guess the only explanation to why I'm getting this wrong on my homework website is that I am entering it in an incorrect format.
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    Find acceleration given initial and final velocity, and displacement

    Wouldn't you still divide by (2s) anyways based on algebra. To get (a) alone you would subtract u^2 from both sides of the equation and have v^2-u^2= 2as. Then you would divide both sides by (2s) to get (a) alone. Isn't that basically the same as the original equation I had? I'm also confused...
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    Find acceleration given initial and final velocity, and displacement

    [b]1. An electron in the cathode ray tube of a television set enters a region where it accelerates uniformly from a speed of 62300 m/s to a speed of 3.86 × 106 m/s in a distance of 3.17 cm. What is its acceleration? [b]2. a = [Vf2 - Vi2] / [2d] [b]3. a = [(3.86 × 106)m/s2 - 62300m/s2]...
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