1. An electron in the cathode ray tube of a television set enters a region where it accelerates uniformly from a speed of 62300 m/s to a speed of 3.86 × 106 m/s in a distance of 3.17 cm. What is its acceleration? 2. a = [Vf2 - Vi2] / [2d] 3. a = [(3.86 × 106)m/s2 - 62300m/s2] / [2 * 0.0317m] I'm getting the answer 2.35(rounded to hundredth place)*1014m/s2 , but it doesn't seem to be correct when I put that answer on my homework. Please help.