Recent content by Echy14

Thanks for the quick reply. Regarding on the fact that you had just said, that was actually my first solution but seeing that they both have the same result. I decided to use this one instead.

If you are going to throw a 1kg ball vertically upward and reach a maximum height of 18m. A)How much energy is needed? B)What should be the initial speed of the ball? My solution: mgh=1/2mv^2 v=√2gh v=√2(9.8)(18) v=18.78m/s In getting the energy I derived the work energy theorem 2w=vo^2...