How to find energy if mass and height is given?

AI Thread Summary
To calculate the energy needed to throw a 1kg ball to a maximum height of 18m, the work-energy theorem can be applied. The initial speed required for the ball is determined using the formula v = √2gh, resulting in a speed of approximately 18.78 m/s. The energy calculated using the work-energy theorem yields 176.34 joules, although there is a suggestion that rounding may have affected accuracy. An alternative method to find energy is to use the equation for gravitational potential energy, mgh, which also provides the same result. Both approaches confirm the relationship between energy, height, and initial velocity in projectile motion.
Echy14
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If you are going to throw a 1kg ball vertically upward and reach a maximum height of 18m. A)How much energy is needed?
B)What should be the initial speed of the ball?

My solution:
mgh=1/2mv^2
v=√2gh
v=√2(9.8)(18)
v=18.78m/s

In getting the energy
I derived the work energy theorem
2w=vo^2
2w=18.78^2
w=176.34 joules
I'm not sure if my answer is correct so I would be extremely grateful if someone could check it.

Thanks.
 
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Echy14 said:
If you are going to throw a 1kg ball vertically upward and reach a maximum height of 18m. A)How much energy is needed?
B)What should be the initial speed of the ball?

My solution:
mgh=1/2mv^2
v=√2gh
v=√2(9.8)(18)
v=18.78m/s
Correct.
Echy14 said:
In getting the energy
I derived the work energy theorem
2w=vo^2
2w=18.78^2
w=176.34 joules
By my reckoning, you are a decimal place off. It is likely a result of your rounding off the velocity.

Note that instead of using the velocity, you could have simply used the fact that work = change in energy = mgh. Do you see?
 
Thanks for the quick reply.

Regarding on the fact that you had just said, that was actually my first solution but seeing that they both have the same result. I decided to use this one instead.
 
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