well, we seem to have an impossible situation here. and in fact we do. if you look at the change in KE of B, it is bigger than the whole of A's KE coming in. this is impossible. these numbers do not correspond to a possible physical situation.
hmm, that doesn't look right. one thing is my fault, you need to change your units from mT to microT.
but the graph itself looks wrong too. it should be symmetric and it should have a minimum at the center. make sure you are adding the fields from the two wires together.
get 10,000 straws and 100m of tape and then start building and dropping. use your intuition to get started, but test, test some more, and then do some more tests; you get the idea :smile:.
yes, you have the idea, now you just need to calculate the field at a few more points and get the shape of the graph. you should try to take advantage of the symmetry of the situation.
notice the field in the middle is 45 microtesla, so you need to adjust your scale.
oops, i just noticed i...
no, all of our action will take place between the wires. you need to make the position of wire 1 = 0cm, and the position of wire 2 = 6cm, and then fill in the rest. the field we are given is for the point located 2cm from wire one, so that is where we plot the value 8.
ok, that should work, though you may need to consider negative B values. Now, we need to partition our axes and give them some units. we can use the one data point that we know already, (2 , 8x10^-6), to help us determine the scale we should use for each axis. the x-axis is easy, just put a...
if you are thinking about the efficiency of the machine, you don't really want to think in terms of initial vs final energy, but rather energy in and energy out. what do you have to put into the thing, this is basically the cost of lifting the bricks, vs the desired output, which is the KE of...