Recent content by ee_mike
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One question about the stability and pole location
Yes, you are right. I think I get the point. Thank you very much.- ee_mike
- Post #16
- Forum: Electrical Engineering
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One question about the stability and pole location
I kind of start to know where I am wrong. Because the laplace transform we are studying is very primary, the requirement on the existence of the inverse laplace transform is much higher. For example for 1/(s-a) we must make Re(s) >a to get the form as you wrote. If Re(s)<a, the expression...- ee_mike
- Post #14
- Forum: Electrical Engineering
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One question about the stability and pole location
At first, thank you for you detailed mathematical expressions. But I still have this question. why such expression don't need to compare Re(s) with a? The inverse laplace transform I leant needs to compare Re(s) with a and gets different expressions. L^{-1} \left(...- ee_mike
- Post #12
- Forum: Electrical Engineering
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One question about the stability and pole location
It's the same,just to have different forms. The requirement for the inverse laplace transform is still Re(s) > *- ee_mike
- Post #10
- Forum: Electrical Engineering
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One question about the stability and pole location
I don't know how to spell that greek character. I use * to replace it. But it doesn't explain how the transient response is determined from Re(s). It gives the result immediately, just an expression of v(t). But with a pole pair at s=(*)+/-jw. The expression is like A/(s-*-wj)+B(s-*+wj). We...- ee_mike
- Post #8
- Forum: Electrical Engineering
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One question about the stability and pole location
The question is at section 8.9.1 How come for different theta's , the inverse laplace transforms are the same for three kinds of theta. you know s=jw and Re(s)=0, so Re(s)<theta , when theta >0- ee_mike
- Post #6
- Forum: Electrical Engineering
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One question about the stability and pole location
The question is at section 8.9.1 How come for different theta's , the inverse laplace transforms are the same for three kinds of theta. you know s=jw and Re(s)=0, so Re(s)<theta , when theta >0- ee_mike
- Post #5
- Forum: Electrical Engineering
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One question about the stability and pole location
but for an expressiong 1/(s-a-bj) + 1/(s-a+bj) where s is only for physical frequencies and is equal to jw. if a>0 , we have Re(s) < a . The laplace transform is different for Re(s) <a ,which gives a result of -exp(-at)u(-t).- ee_mike
- Post #3
- Forum: Electrical Engineering
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One question about the stability and pole location
I have a question related to that is explained on the textbook Sedra & Smith. for a pole at s=a+bj,say, 1/(s-a-bj) why can we have the time domain of the signal to be exp(at+jbt)? It is strange because s=jw, so Re(s)=0 <a ,which leads to the solution to be -exp(-at-bjt)u(-t), so that...- ee_mike
- Thread
- Pole Stability
- Replies: 15
- Forum: Electrical Engineering
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Graduate A question about solving the energy eigenvalue of a given Hamiltonian operator
You are so powerful. I have been doing on this problem since this morning. Thank you very much.- ee_mike
- Post #5
- Forum: Quantum Physics
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Graduate A question about solving the energy eigenvalue of a given Hamiltonian operator
Could you explain more detailedly? Because I wonder what is the eigenvalue of a(x+\frac{b}{2a})^2 - (\frac{b}{2a})^2 Thank you very much, you really helped me.- ee_mike
- Post #3
- Forum: Quantum Physics
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Graduate A question about solving the energy eigenvalue of a given Hamiltonian operator
The problem is A particle of mass m and electric charges q can move only in one dimension and is subject to a harmonic force and a homogeneous electrostatic field. The Hamiltonian operator for the system is H= p2/2m +mw2/2*x2 - qεx a. solve the energy eigenvalue problem b. if the...- ee_mike
- Thread
- Eigenvalue Energy Hamiltonian Operator
- Replies: 4
- Forum: Quantum Physics