Recent content by ElBell

Thanks for your help! What does everything think of what I have done here? Eo= Ei(R1/R1+R2) – (R3/R3+R4) Eo= 3V (100/100+150) - )200/250+300) = -.164V Let us change R1 to 125 ohms: Eo= Ei(R1/R1+R2) – (R3/R3+R4) Eo= 3V (125/125+150) - )200/250+300) = 0V

Homework Statement A bridge initially has resistances equal to R1=100ohms, R2= 200ohms, R3= 250ohms, R4= 300ohms. Determine output voltage at this condition for an input voltage of 3V. What is the bridge output if R1 changes to 125ohms? Homework Equations Havent been given any. I am...

Hi Everyone, Question: Mean is 0.252, standard deviation is 0.003, permitted tolerance of 0.246 to 0.258. What percentage of washers will be discarded. Attempt: I am so stuck. I have looked at my text and online for hours and know that it should be fairly easy but I am getting stuck...

OK thanks so much! This is what I now have: T at 0 degrees: R= 12/ 0.12 = 100 ohms T at 100 degrees: 100/2^(100/46) = 22.2 ohms R= 12/ 0.795= 15.094 ohms So: 15.094= 100/2^(T/46) 2^(T/ 46)= 100/ 15.094= 6.625 (T/46)log 2= log 6.625 T/46 = log(6.625-2) ? is this...

pat666, you are a champion :) Thankyou.

Thanks for your help so far: Can anyone help with part two? So far I have equations: W= 1/2kx^2 F=kx (so k= f/w)?? So: k= 3.6/ 0.096= 37.5 W= (1/2)(37.5)(0.096^2) W= 0.1728J ----does anyone know if this appears correct?

Stress= 3.6N/ (4* 10^-6) Stress= 900000 Strain= .096/ .80 Strain= 0.12 Y= 900000/ 0.12 Y= 75* 10^5 ?

I got .8 because it was .8 of a metre? previously i had 80cm written in but i guessed because we are using metres, .8 would have been the correct input?

OK, sorry for this, but now I am totally confused. Is the answer I had originally correct? 750? Or is my new answer correct? haha!?

Ooooh OK I see what you are saying. Stress= 3.6N/ (4* 10^-6) Stress= 900000 Strain= 900000/ .80 Strain= 1125000 Y= 90/ 1125000 Y= 8^-5 :( Now I am confused...and hopeless!

I know that at 0deg celsius it is 120mA and at 100deg celsius it is 540mA. Are these the figures I would use to calibrate, and how would I go about doing this? Thanks a lot :)

sorry, also forgot to mention that for some reason we are never given the lengths! I assume because we are using percentages I could just input the easiest figure and the result will always be the same??

Thanks for your help so far! I understand from your help on my last question that you don't square your numbers, but I havent. I thought I had to change my units to metres, so I changed 4 o (4*10^-2)? Maybe I should have just written 0.004 to save confusion. Am I right in even converting...

No I didnt receive an answer from teacher, I formulated it myself but it appears I didnt get it right! Thanks so much for your help, I know I am lacking the basic knnowledge for this but I am doing my best :)

When I take onboard the tips you have given me, I get the same answer as you! I thought (10* 10^10) was the same as (10^10)? Anyway, I also received an answer of 30000. Is that the final answer? Do I need to do something with the results? Isnt that too big?