Solving a Bridge Circuit: Input Voltage, Resistances, and Output Voltage

[ElBell]

Homework Statement

A bridge initially has resistances equal to R1=100ohms, R2= 200ohms, R3= 250ohms, R4= 300ohms. Determine output voltage at this condition for an input voltage of 3V. What is the bridge output if R1 changes to 125ohms?

Homework Equations

Havent been given any. I am assuming something to do with Ohms Law?

The Attempt at a Solution

I used Ohms Law. But I don't know if I am on the right track.

I= E/ R
I= 3/ 850 = 0.00353 amps.

Now I don't know what to do. Or if I was even supposed to use this Law.

Any help would be much appreciated :) Thanks a lot.

 

[iced_maggot]

I'm actually just learning about them myself so I could be wrong but I may be able to help. Firstly the equivalent resistance of parallel resistors isn't just the sum of resistances so that doesn't work because in a bridge you usually have two banks of resistors that are in series connected in parallel which is in turn connected to some sort of measuring device (galvanometer) at a point in between them.

So across that measuring device, you will have a positive and negative terminal and you want the potential difference between them

So, voltage across top of the circuit (current flows in direction of positive charge) = V = 3v

So the voltage in the (+) terminal is = V x (R2/ R(eq) of R1 and R2 in serial)
voltage in the (-) terminal is = V x (R4 / R(eq) of R3 and R4), just find the difference between them and I think that should be it.

 

[ElBell]

Thanks for your help!

What does everything think of what I have done here?

Eo= Ei(R1/R1+R2) – (R3/R3+R4)
Eo= 3V (100/100+150) - )200/250+300)
= -.164V
Let us change R1 to 125 ohms:

Eo= Ei(R1/R1+R2) – (R3/R3+R4)
Eo= 3V (125/125+150) - )200/250+300)
= 0V

 

[vk6kro]

The method looks OK except you seem to be using the wrong values for some of the components.
R1=100ohms, R2= 200ohms, R3= 250ohms, R4= 300ohms in the first post.

You are using 150 ohms for R2 and 200 ohms for R3.