This is the problem given:
A skier leaves the horizontal end of a ramp with a velocity of 25.0 m/s east and lands 70.0 meters from the base of the ramp. How high is the end of the ramp from the ground?Relevant Equations:
Vy=Vsin
Vx=Vcos
T=(2Vsin/g)
H=(Vsin)^2/2g
R=2V/g(sin)(cos)
X=Vi(T) +...