This is the problem given: A skier leaves the horizontal end of a ramp with a velocity of 25.0 m/s east and lands 70.0 meters from the base of the ramp. How high is the end of the ramp from the ground? Relevant Equations: Vy=Vsin Vx=Vcos T=(2Vsin/g) H=(Vsin)^2/2g R=2V/g(sin)(cos) X=Vi(T) + (1/2)a(t)^2 My attempt I drew a picture with the ramp horizontally, a vertical line coming off of the end of it for the height, and a parabolic curve by the vertical one to represent the path the skier took. then I wrote what I know: a= -9.81 m/s d=70.0 m t= ? V initial =25.0 m/s V final = ? And now I really have no idea how to find the height of the jump. Finding the time wouldn't help because time shouldn't affect the height of the jump. And finding the velocity wouldn't help either because velocity shouldn't affect the height of the jump either. And it doesn't seem like I can use sin/cos/tan equations because I don't have a right triangle. so any help is appreciated thanks! I'm at the end of my rope!