Recent content by erpelkon

  1. erpelkon

    Finding the currents in this circuit (2 voltage sources and 3 resistors)

    But after calculus one will find out I1 to be the largest and not I3, thus U1 has to be a load and not a source?
  2. erpelkon

    Finding the currents in this circuit (2 voltage sources and 3 resistors)

    So basically higher voltage U2 is "charging" lower voltage U1 since given the orientation of U1 the current is reversed! Agreed!
  3. erpelkon

    Calculate the voltmeter reading for this circuit with 2 sources and 2 resistors

    Current returning to cell A = x Current returning to cell B = y Current entering the voltmeter = z 10- 1*x=0 4- 2*y = 0 z = y + x X=10 Y=2 Z=12 U=RI 1/R=1/1+1/2 1/R=1,5 R=2/3 U = (2/3)*12 = 8 The reading is 8 Volts.
  4. erpelkon

    Finding the currents in this circuit (2 voltage sources and 3 resistors)

    How come? Clockwise, i.e. U2 is positive direction and U1 is negative direction.
  5. erpelkon

    Finding the currents in this circuit (2 voltage sources and 3 resistors)

    Substitute I3=z, I2=y and I1=x. System of equations: z = y + x 12−0.2z−0.02x=0 −10+0.2z+0.1y=0 From second and third equation solve: x=−10z+600 y=100−2z Add these to the first: z=(100−2z)+(−10z+600) z=700/13 z~53,85 Thus I3~53,85 , I2~-7,7 and I1~61,5 Hope this helps!
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