Recent content by f.wright

Say you measured the position of a particle and found it to be at x1, then you waited a period of time, Δt, and measured it again and find it at x2 and kept repeating your measurements over the same time period finding positions x3, x4 etc. In this case the observable is particle momentum...

I think your proposal is overly ambitious. For NMR and EPR to work you have to have a steady homogeneous B field over the resonant sample (or at least know how the B field varies over space). Take out your gaussmeter and walk around the lab and you will see that the Earth's magnetic field is...

San K, Read the Wikipedia article on Electromagnetically induced transparency. You will see that the answer to your question 1 is no. The answer to question 2 is yes. As far as question three goes; when light passes from a medium of lower refractive index to a medium of higher refractive...

If you look up the Hall effect on Wikipedia you will see that the Hall coefficient for semiconductors depends on the concentration of the two types of charge carriers as well as their respective mobilities. N doping means electron charge carriers predominate. Look at their expression for the...

The first four chapters or so of Tinkham are related to crystallographic symmetry groups. The math is not hard at all. If you can do the problems in Kittel, you can work through Tinkham. I suggest you read the first few chapters and try to work the problems. The time spent studying group...

Google “High Pressure Effects on the Crystal and Magnetic Structure of Pr0.1Sr0.9MnO3 Manganite” N.T. Dang et al. This paper may give you some insight to your questions. They show neutron diffraction spectra of A-type AFM, C-type AFM and G-type AFM along with analysis.

You need to study a little group theory as it applies to crystallographic symmetries. It is surprisingly easy to understand. I leaned it from the book by Micheal Tinkham "Group Theory in Quantum Mechanics". Basically, the geometric structure of the Wigner Seitz cell is subsumed to an...

Why don’t you complete the square in the integral? let a = α2/2 + ipt/2mhbar b = ix/hbar + ipt/2mhbar e-(a + b*b/4a*a)∫qe(b/2a-q)*(b/2a-q)dq and making the substitution q’ = b/2a-q I get e-(a + b*b/4a*a)[(b/2a)e-q’*q’-√(π/4)erf(√q’) ] --sorry about the notation. I don't know how to...

bullet problem The force on the bullet in the x direction is Fx = m(d2x/dt2) = 0. The force on the bullet in the y direction is Fy = m(d2y/dt2) – mgy = 0. Integrating the first equation twice w.r.t. time we get x = << Too much detailed help deleted by Mentors >>

If the thermally generated charge carriers in the depletion region persisted for a time on the order of the time required for the E field to establish thermal equilibrium(in the Gibbs sense), then the thermal noise signal would swamp out the radiation signal. The average E field amplitude...

If they didn't, there would be no existence. Atoms could't form. There would be no light. Subhan Allah wa bihamdihi

JJ zero bias conductance The current through the JJ is due to tunneling of Cooper pairs. Unlike quasiparticle tunneling, pair tunneling does not involve excitations and can occur even without bias across the junction. Thus one could connect a current source to a junction and, for currents less...